X-Mozilla-Keys:                                                                                 

Paul wrote:

Yvon Cournoyer wrote:

Good evening Paul,

The chart I have says:  -80F=62.2C and -70F=56.7C

The following formula gives me: C=5/9 (F+40) -40
C=5/9 (-71F+40) -40 = -57.2C.

Cordially,
Yvon Cournoyer
13B powered Zenair Zenith (CH200)  C-FCPB

You guys up in Canada always seem to know this stuff for
some strange reason. Is it cold up there? :-)

Paul Lamar

Finn Lassen wrote:

I think this is the right formula:

C=5/9 (F-32)
F=9/5C + 32

Test: water boils at (sea level) 100C and 212F.

Finn

And 0 degree C is 32 degree F.

BTW What is the status of your airplane Finn?

Paul Lamar
 
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