X-Mozilla-Keys:                                                                                 
Ed Anderson wrote:

Brian,

 Talking your injectors I calculated the following:

                     Coversion
Gallons/hr for
                         Gallons x 60 =    Gallons/hr         x2 injectors
550 cc/min     0.1452946          8.717676           17.435352
720 cc/min     0.1902039         11.412234          22.824468

    Total Gallons/hr = 40.25982   Lbs/hr = 241.55892

First, I converted your cc/min into gallons/hr (sorry, I can just do better
in engish units) and then x2 injectors to come up with a grand total of 40
gph or 241 lbs/hr.  If you used the frequently quoted BSFC for a rotary of
.55 this would equate to approx 241/0.55 = 438 HP.  Looking for the air mass
then at air/fuel ratio of 12:1 would give 12x241 = 2892 lbs of air/hour or
48.2 lbs/min to go with your 241/60 = 4.016 lbs/min of fuel.  Checking 48.2
lbs/min of air divided by 4.016 lbs/min of fuel = 12:1 Checks!

  Hope this  helps

Ed Anderson

The Aircraft Rotary Engine Newsletter.              Powered by Linux.

http://home.earthlink.net/~rotaryeng/            http://www.linux.org