Subject: Ignition Timing
From: Paul
Date: 8/15/2000, 11:42 PM


<< Peter Nunn wrote:
 >
 > Thanks for the info it would appear then that the rotor rotates at 1/3 the
 > eccentric shaft, the 'distributor' rotates at 1/2 that so the ratio is >>

The rotor turns at 1/3 the e-shaft speed, in spite of the number of teeth, so
when the e-shaft turns 6 turns, the rotor turns 2 turns and the distributor
turns 3 turns.  Take your pick of how you want to express the ratio.

Bob Darrah


 
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