Subject: Next question.
From: Paul
Date: 4/25/2001, 3:15 PM



160 lbs each for the front mounts, 80 lbs for the rear, ASSUMING that the
front mounts are symmetrically positioned about the thrust line, and the rear
mount is axially aligned with the thrust loading.

If I am correct, I will give up the marine industry and join you aviators.

Jon Lauter
Rotary Power Marine Corporation


Welcome to aviation Jon :-)

Here is how I did it. This is all I could come up with as my mind was a blank.

First column is deflection. Second column is big bushing load. Third column
is little bushing load.  Last column is total load.
I always tell young math and science students to learn to program in
BASIC as soon as possible :-)

Paul Lamar
 
The AirCraft Rotary Engine NewsLetter.              Powered by Linux.

http://home.earthlink.net/~rotaryeng/            http://www.linux.org

BUSH.DAT
.30   120    60   300
.31   124    62   310
.32   128    64   320
.33   132    66   330
.34   136    68   340
.35   140    70   350
.36   144    72   360
.37   148    74   370
.38   152    76   380
.39   156    78   390
.40   160    80   400
.41   164    82   410
.42   168    84   420
.43   172    86   430
.44   176    88   440
.45   180    90   450
.46   184    92   460
.47   188    94   470
.48   192    96   480
.49   196    98   490
.50   200   100   500

BUSH.BAS
'calculates the load on rubber bushings
rate1 = 400
rate2 = 200
OPEN "bush.dat" FOR OUTPUT AS #1

FOR x = .3 TO .5 STEP .01

bigbush = rate1 * x
littlebush = rate2 * x
load = 2 * bigbush + littlebush
PRINT #1, USING ".##"; x;
PRINT #1, USING "######"; bigbush;
PRINT #1, USING "######"; littlebush;
PRINT #1, USING "######"; load
NEXT x
CLOSE

SHELL "more < bush.dat"
SYSTEM