Here is how I did it:

Basic equation is F=kx.

Front mounts in parallel, k= twice the given rate, so Ffront = 800 x
Rear mount, Frear = 200 x
x is the same front and rear as we assume the engine and mount frames are
perfectly rigid.

So Ftotal = (200x + 800x) = 400 lbs.
solve for x = .4

Ffront = 320 lbs, or 160 per mount
Frear = 80 lbs.

Jon Lauter
Rotary Power Marine Corporation

 
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