Craig Spence wrote:

Can anyone advise me of the required (optimum) thermal rejection rate

(BTUs)

for a Mazda 13B rotary oil cooler for an aircraft installation?
Regards
Craig Spence
Cobra Aviation - Australia

The oil is one third of the total cooling requirements. You can determine
that from this WOT heat balance chart for a 13B. For example; assume
the basic engine is 200 HP net representing 28% of the total heat in a

gallon

of gas. Total theoretical heat in the fuel would then .28 x Total Heat =

200 HP

Total Heat in the fuel is therefore 200 /.28 or 714 HP.

From the chart the oil cooling is about 8% of that so .08 times 714 HP
is 57 HP. One HP is equal to 2545 BTU's per hour. Oil cooling is therefore
145,065 BTU's per hour.

BTW turbo compounding is a hot topic lately so 45% of the 714 HP
or 321 HP goes out the exhaust in the form of waste heat.

Paul Lamar

Craig Spence,
I have been watching your progress on the 13B installation and was wondering
when you were going to tackle the cooling problems associated with the
Mazda.
Tommy said it was all sorted-out.
Best of luck with that, as you are space limited.
Not that it can't be done, but it must be done well to cool the beast.
Although the RX8 engines are a little easier to cool.

BTW who supplies your PSRU, I believe their from NZ?
George ( down under) - Brisbane.

 
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