I am about to spend big bucks so I would like you
young engineers that grew up on meters Kg Newtons
to check some numbers for me.

radius = .9685 inches  meters = ??
Circumference = 6.085  meters = ??
RPM = 10,000
Velocity = ???? meters per second

Weight .3233 pounds  Kg = ????

Force Newtons = m x V^2 / r

m in Kg
V in meters per second

Force in Newtons ??
Force in pounds?

I think the answer is 88 pounds.

Hi Paul;

Lets see;
A newton (N) is the force required to accelerate a 1 kg mass 1 m/s^2.  1
lb = 4.448N, 1kg = 2.205 lbs
For uniform circular motion, F = ma = m * v^2/r
r = .9685  in = .9685 * 2.54 = 2.46cm
circumference = 6.085 in * 2.54 = 15.46 cm /100 = 0.1546m
RPM = 10000 = 166.7 revolutions per second
Velocity = 167.7 * 15.46 cm = 2577 cm/s / 100 cm/m = 25.77m/s
Weight = .3233 lbs = .3233 / 2.205 = .1466 kg

F (newtons)   = m x V^2/r
                   = (.1466kg) * (25.77)^2 m/s^2 / (0.1546m)
                   = 629.7N / 4.448
                   = 141.6 lbs centripetal force

Someone check my numbers.

Cheers
Cary

Thanks Cary. I messed up on converting the .3233 pounds to Kg.
That is the centrifugal load on the outer ring from the roller
and shaft on the traction box. I have come up with a way around that
and had to check my numbers. I will upload a 3D shortly as I think
it will greatly improve a traction drive with output from the
planet carrier.

I had calculated it using  inches and pounds but I was not sure
about the units in the equation F = m x V^2 / r my old physics book
is at the house 65 miles away. Thanks again Cary.

Paul Lamar ...No rotor no motor.

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