Do you think a 1/8th fitting will flow enough fuel at 2-3 lbs
    pressure? Karibian

    I think so but I am going to do a few flow tests when
    I get a chance. Two psi is a 4.43 foot head.

    Here is a theoretical chart for flow orifices sizes using two psi.
    A jic 1/8th 37 degree flare fitting has an ID of .175". The HP
    numbers are based on a .55 BSFC as I recall.

    These will be for one rotor only. The main feed line for
    both rotors will be larger.

    The last chart is for a one cylinder piston engine so
    that is half a rotor.

    Paul Lamar ...No rotor no motor.

    Paul,

    How id you get 4.43 ft of head? Did you take the specific gravity of
    gasoline into account?

    Head = Pressure (psi) * 2.31 / Specific Gravity

    SG of gasoline ranges between 0.68 and 0.74, if we take 0.71 as an
    average, we get a head of: 2 psi * 2.31 / 0.71 = 6.5 ft.


    Regards,

    Gordon.


That chart is just a ball park check of flow.
The formula I found and used from the web is suspect.
That is for water as I recall. 65 pounds per cubic foot.
Or .45 psi per foot. 4.43 x .45 psi is 1.999 psi.

Aviation fuel weighs 6 pounds per gallon. One gallon is 232
cubic inches. One cubic foot is 1728 cubic inches.
One cubic foot is therefor 7.44 gallons times 6 pounds is 44.68
pounds. Doing it another way water weighs 8 pound per gallon
and fuel weighs 6 pounds per gallon so 6/8 X 65 pounds is
48.75 pounds per cubic foot. It all depends on the phase of
the moon :) Actually depends on the temperature.
Car racers cool the fuel in the pit tanks to get more weight
of fuel in the 100 gallon limit tanks.

Take 50 pounds per cubic foot or .34 psi per foot.
Then two psi /.34 is  5.88 feet head.

I am using a pressure regulator so all that is academic.

BTW here is the latest 3D. I used a solid 1 inch hex
stock as it is easier to drill and tap for the fittings.

Also the fuel system schematic. The blue thing is the pressure
regulator. The gold things are the Facit pumps and the yellow
thing is the fuel filter. A gascalator(s?) could be added on the
front side of the firewall.

Paul Lamar ...No rotor no motor.

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CLS

'  12 " water =  .45 psi
'  1"   water =  .0376157 psi
'  12 " fuel =  .33854 psi
'  1"  fuel = .0282118 psi
'  2 psi =  53.169 5nches 0f water or 4.43 feet
' Q = A * V
' Q cubic feet per second
' A area in square feet
' V velocity of water in feet per second
' V = 8.02 * (4.43) ^ .5
' Q = A * V


PRINT
PRINT
PRINT " 2 psi = 4.43 feet head"
V = 8.02 * (4.43) ^ .5

PRINT
PRINT " Diameter  Area sq inches  Area sq feet   Pounds/hr      HP       GPH"

FOR D = .016 TO .109 STEP .003
PRINT USING "##.###"; D;
R = D / 2
A = R ^ 2 * 3.1416
PRINT USING "######.#######"; A;    'Area in square inches
Af = A / 144
PRINT USING "#######.########"; Af; 'Area in square feet

Q = Af * V    'Q in cubic feet per second
P = Q * 48.75 'pounds of fuel per second
P1 = P * 60   'pounds of fuel per minute
P2 = P1 * 60  'pounds of fuel per hour
PRINT USING "##########.##"; P2;

HP = P2 / .6
PRINT USING "########.##"; HP;

GPH = P2 / 6
PRINT USING "#######.##"; GPH


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