Paul,
Any idea of the thermal efficiency of the rotary engine?
Or if we have reliable fuel flow and horsepower figures we can figure
it out using the formula:
TE = 0.1338 8 * HP / FF (in pph)
Regards,
Gordon.
Somewhere aroud 28%.
Paul Lamar
Paul,
Can we assume that the turbocompound engine should see about 35
percent? This would represent about a one-third increase, due to the
energy recovered.
Btw, I'm surprised at the 28 percent figure. This is about the same
as the air-cooled Lycoming. The Continental IO-550 used in Columbia
350 works out to about 31 percent, which is very very good.
Regards,
Gordon.
Probably not quite that high. 35% that is.
Here are some heat balance charts.
--
Paul Lamar ...No rotor no motor.
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