Since the displacement of piston engines is based on the volume a piston
displaces in one stroke times the number of cylinders, I would say
the 13B rotary displacement is the volume of one rotor face on the
intake phase times six. Karibian


You are too late for the contest Hurant.

I am still waiting for all the votes to come in.

Paul Lamar ...No rotor no motor.

Too bad you are too late Kariban, but your answer is being noticed.
However, please consider this question:
Does a single rotor not just have one 'cylinder' and one rotor (piston) ?
A 13B then has two 'cylinders' and two rotors. Why to multiply by 6 ?

The fact that the rotor turns over does not make it three rotors.
On one crank shaft rotation, like in a two stroke, one chamber fires and
one chamber volume is being displaced in a power stroke.
That is the same as in a two stroke RPE. The Wankel rotary is similar to
a two stroke reciprocating piston engine.
And since the Wankel operates on the four-stroke cycle, it likely should
be compared to a four-stroke RPE and the displacement should be counted
that happens at two shaft rotations.
Doing that, the 13B would be equivalent to a 2.6 liter four-stroke RPE
and the same volume is being displaced, or 'burned', at equal rpm.

Rolf



The Rotary Engine NewsLetter. Powered by Linux.
ACRE NL web site. http://www.rotaryeng.net
Copyright 1998-2007 All world wide rights reserved.