When I compile this extremely simple program I get this cryptic error:

"warning: passing argument 1 of "printf" from incompatible pointer type"

Here is the program.

# include <stdio.h>

int main()

{
printf(stdout, "this is a test\n");
}

What ever could be wrong? :)

-----------------------------
Never mind. Incompatible versions of C.
The program source was from an earlier version.
Here is the corrected source:

# include <stdio.h>

int main()

{
printf("this is a test\n");
}


Now it apparently compiles it but I can not find the executable.
Anybody have any idea where gcc  hides it? :)

Paul Lamar