Subject: Ring gear shear load.
From: rotaryeng
Date: 1/23/2012, 9:49 PM
To: AAAA Put this in the To box

Ed, The big sun gear is 2.25 inches in diameter.
so tooth torque  load is 200 foot pounds or 2400 inch pounds.
so the tooth shear load is 2400 inch pounds divided by 1.125 or
2,133 pounds. The same tooth load is applied to the ring gear teeth.

The 2.85:1 ring gear is 5 inches in diameter with a circumference of 15.7 inches. It is 2 inches wide so the area is 31.4 square inches.
Therefor the shear load is 2,133 pounds divided by 3.4 or 68 pounds per square inch shear. Well within the capability of red RTV. In other words we can just glue the ring gear to the housing with red silicone rubber. Make a real thin aluminum steel RTV sandwich one square inch in area and see how much load it will take in shear.

Your front planet shafts are the same size as mine. .440 or so.
The torque load on the bolts is 2.85 times 200 foot pounds or 570 foot pounds. That is 6840 inch pounds. Bolt circle is 3.3 inches. Radius is 1.65 inches so total shear on the six bolts is 4,145 pounds. There are six bolts so each bolt must take 690 pounds shear. If we EDM them out to 5/16 and use 5/16 bolts.  The bolt diameter .3125. Pi X r squared for the area. Area is.0767 each bolt. 690/.0767 then bolt shear stress is then 8,996 in each bolt.

Piece of cake. Even cheap bolts will take 100,000 psi.

As a belt and suspenders we can add six 3/8th dowel pins between the bolts. The 5/16th bolts will then just hold the works together.


Check my arithmetic.

Paul Lamar

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