<http://www.engineeringtoolbox.com/stress-thin-walled-tube-d_948.html>


When a thin-walled tube or cylinder is subjected to internal pressure a hoop and longitudinal stress are produced in
the wall.
Hoop Stress

The hoop stress can be expressed as:

σh = p d / 2 t (1)

where

σh = hoop stress (MPa, psi)

p = internal pressure in the tube or cylinder (MPa, psi)

d = internal diameter of tube or cylinder (mm, in)

t = tube or cylinder wall thickness (mm, in)

Longitudinal Stress

The longitudinal stress can be expressed as:

σl = p d / 4 t (2)

where

σl = longitudinal stress (MPa, psi)

p = 200 psi
d = 2"

pd = 400

t = .032
2 x .032 = .064

σh = 200 x 2 / .064  = 6250 psi very low for steel.

At 200 psi we can get 600 pounds of force out of the
shock. Piece of cake! No die springs needed.

I was needlessly worried. No need to get the lower eye off.
Use as is. Maybe save 3 pounds by shortening it later.


Paul Lamar

Great news, simpler and no work to convert it after all,

Alex

-- The Rotary Engine News Letter. Powered by Linux.
ACRE NL web site. http://www.rotaryeng.net
You Tube http://tinyurl.com/beqqxas
Copyright 1998-2013 All world wide rights reserved.